12x^2+60x-600=0

Solution for 12x^2+60x-600=0 equation:

12x^2+60x-600=0

a = 12; b = 60; c = -600;
Δ = b2-4ac
Δ = 602-4·12·(-600)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-180}{2*12}=\frac{-240}{24}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+180}{2*12}=\frac{120}{24}
=5
$